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Aptitude questions for TCS aspirants.

Aptitude questions for TCS aspirants

TIME AND WORK :

1) A can do a piece of work in 10 days and B can do the same work in 15 days , In how many days both will finish the work ?

 

L.C.M of 10 and 15 = 30( Total work )

Total work

Persons

Per day work

10

A

3

15

B

2

 

Total per day work = 3+2=5

Both will finish the work in 30/5 = 6 days.

 

2) A can do a piece of work in 12 days and B can do the same work in 15 days , In how many days both will finish the work ?

 

L.C.M of 12 and 15 = 60( Total work )

Total work

Persons

Per day work

12

A

5

15

B

4

 

Total per day work = 5+4=9

Both will finish the work in 60/9 = 6 2/3  days.

 

3)A and B together do a piece of work in 15 days ,A can alone do it in 20 days ,In how many days B alone can do the work ?

 

A+B=15

A=20

 

L.C.M =60

 

Work done per day , A= 3, A+B= 4 , so B = 1

 

Therefore  B can complete a work in 60 days .

 

4)A can complete the work in 25 days , B can do it in 20 days , they start the work together after 5 days ,A left , B will do the remaining work in how many days?

 

A=25

B = 20  è L.C.M = 100 ( TOTAL WORK)

 

Total work

Persons

Per day work

25

A

4

20

B

5

  For first 5 days both A and B worked together  à 9*5 = 45

45 works are completed ,remaining works= 55

 

B will complete it in = 55/5 = 11 days.

 

 

5) A can complete the work in 10 days , B can do it in 15 days , they start the work together after 3 days ,B left , A will do the remaining work in how many days?

 

A=10

B = 15  è L.C.M = 30 ( TOTAL WORK)

 

Total work

Persons

Per day work

10

A

3

15

B

2


15 works are completed ,remaining works= 15

 

A will complete it in = 15/3 = 5 days.

 

6) A can complete the work in 25 days , B can do it in 20 days , A started the work

And after 10 days ,B also joined  him , How many days the work lasts ?

 

 

A=25

B = 20  è L.C.M = 100 ( TOTAL WORK)

 

Total work

Persons

Per day work

25

A

4

20

B

5

 

A worked for 10 days , work completed is 40

 

Remaining work = 60

 

The  remaining work wil be completed in 60/9 =6 2/3 days

 

Total no of days = 10+6 2/3 days =  16 2/3 days

 

7) A can complete the work in 10 days , B can do it in 15 days , B started the work

And after 5  days,A also joined  him , How many days the work lasts ?

 

A=10

B = 15  è L.C.M = 30 ( TOTAL WORK) 


Total work

Persons

Per day work

10

A

3

15

B

2

 

B worked for 5 days , work completed is 10

 

Remaining work = 20

 

The  remaining work will be completed in 20/5 =4 days

 

Total no of days = 5 + 4 days =  9 days

 

8)A can do a work in 45 days  and B in 40 days , They work together , After  Some days, A left .B wil do remaining work in 23 days , After how many days A left ?

 

A=45

B = 40 è L.C.M = 360 ( TOTAL WORK)

 

Total work

Persons

Per day work

45

A

8

40

B

9

     B worked for 23 days = 9*23 = 207

Remaining work = 360-207 = 153

 

A left in = 153/117=9 days

 

9)A complete work in 24 days , B in 36 days , & C in 48 days . They start working together .After 4 days , C left ,A left  3 days before completion of work , The work last for how many days ?

 

A-24

B- 36

C-48  à L.C.M = 144

 

Total work

Persons

Per day work

24

A

6

36

B

4

48

C

3

 First 4 days all together = 13 * 4 =52

 

52+12=64

 

80/10= 8 days.

4+3+8=15 days

 

10)A can complete in 12 days , B in 16 days ,C in 24 days .They all started the work together After 2 days C left , A left 3 days before  completion of work ,the work last for ??

A-12

B- 16

C-24  à L.C.M = 48

 

Total work

Persons

Per day work

12

A

4

16

B

3

24

C

2

 First 2 daysall together = 9*2 =18 

18+9=27

21/7= 3 days.

2+3+3=8 days


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